Overview
A function \(f\) is even if
\[ f(-t) = f(t) \quad \text{for all } t, \]
and odd if
\[ f(-t) = -f(t) \quad \text{for all } t. \]
Taking \(t = 0\) shows that an odd function defined at \(0\) has
\(f(0) = 0\).
Symmetry of the graph
- The graph of an even function is unchanged by reflection in the
\(y\)-axis, \((t, y) \mapsto (-t, y)\).
- The graph of an odd function is unchanged by rotation through
\(180^\circ\) about the origin, \((t, y) \mapsto (-t, -y)\), which is
the same as reflection in the \(y\)-axis followed by reflection in the
\(t\)-axis.
Integrals over \([-a, a]\)
\[ \begin{aligned}
f \text{ even:} \quad & \int_{-a}^{a} f(t) \, dt = 2 \int_0^a f(t) \, dt \\
f \text{ odd:} \quad & \int_{-a}^{a} f(t) \, dt = 0
\end{aligned} \]
For an even function the areas over \([-a, 0]\) and \([0, a]\) are
equal; for an odd function they are equal in size and opposite in sign,
so they cancel. The integral must exist: \(\int_{-1}^{1} \frac{1}{t^2} \, dt\)
diverges, and \(\int_{-1}^{1} \frac{1}{t} \, dt\) is not \(0\), because it
does not exist.
Sums and products
- even + even is even, and odd + odd is odd.
- even × even and odd × odd are even; even × odd is odd.